top of page

CCC 2018 J1: Telemarketer or not?


Simple if-else statement by comparing numbers meeting these conditions:

•the first of these four digits is an 8 or 9

• the last digit is an 8 or 9

• the second and third digits are the same

it will output "ignore" otherwise it will output "answer"

def call(a):
    if (a[0] == 9 or a[0] == 8) and a[1] == a[2] and (a[3] == 9 or a[3] == 8):
        print("ignore")
    else:
        print("answer")

A = []
for i in range(4):
    A.append(int(input()))

call(A)

Recent Posts

See All

CCC '24 J5 - Harvest Waterloo

#include<iostream> #include <vector> #include <algorithm> #include <cmath> #include <stack> using namespace std; int main() { int r, c,...

CCC '24 J4 - Troublesome Keys

s1 = input() s2 = input() silly = '' silly_o = '' quiete = '-' i = 0 j = 0 while i < len(s1) and j < len(s2): if s1[i] != s2[j]: if...

CCC '22 J5 - Square Pool

#include<iostream> #include <vector> #include <algorithm> #include <cmath> using namespace std; bool rowcom(pair<int, int> a, pair<int,...

コメント


bottom of page